The r.m.s. current in an ac circuit is 2 A. If the watt less current be √3 A , what is the power factor
iwL=irms sinϕ ⇒ √3=2sinϕ⇒ sinϕ =√32 ⇒ ϕ=60∘ so p.f =cosϕ=cos 60∘=12.
In the circuit, as shown in the figure, if the value of R.M.S current is 2.2 A, the power factor of the box is