The radial wave function of an orbital is 2Za032 eZr-a0 for H-atom- The wave function is for- notations have their usual meaning

The correct option is A 1 s For 1s orbital p(θ) =1√(2) Radical wave function =2Z^3/2a_o^3/2e^Z_r/ a_o=2(Za_o)^3/2e^Z_r/ a^o ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Schrodinger Equation

The radial wa...

Question

The radial wave function of an orbital is $2 {(\frac{Z}{a_{0}})}^{\frac{3}{2}} e^{\frac{Z r}{- a_{0}}}$ for $H -$ atom. The wave function is for: (notations have their usual meaning)

1 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 p

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 p

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

1 s

R (r) = \frac{1}{\sqrt{π}} {(\frac{1}{a_{0}})}^{\frac{3}{2}} e^{\frac{- r}{a_{0}}}

a_{0} = 0.529 \circ A

r = a_{0}

(x . e^{- y})

(x + y)

ψ = \frac{1}{16 \sqrt{3}} {(\frac{1}{a_{0}})}^{\frac{3}{2}} [(x - 1) (x^{2} - 8 x + 12)] e^{- \frac{x}{2}}

x = \frac{2 r}{a_{0}}; a_{0} =

1 s

R (r) = \frac{1}{\sqrt{π}} {(\frac{1}{a_{0}})}^{3 / 2} e^{- r / a_{0}}

a_{0} = 0.529 A \circ)

r = a_{o}

^{- y}

- Ψ = \frac{1}{81 \sqrt{6 π}} (\frac{1}{a_{0}}) \frac{3}{2} σ e^{\frac{σ}{3}} (3 c o s^{2} θ - 1); H e r e σ = r / a_{0} a n d a_{0} = \frac{h^{2} ϵ_{0}}{π m e^{2}}

Ψ_{3 s} = \frac{1}{(81) \sqrt{3 π}} {(\frac{1}{a_{0}})}^{\frac{3}{2}} [27 - \frac{18 r}{a_{0}} + \frac{2 r^{2}}{a_{0}^{2}}] e^{\frac{- r}{3 a_{0}}}

\frac{d}{1.5 a_{0}}

\sqrt{108} = 10

Join BYJU'S Learning Program