Question

The radii of circular ends of a bucket of height $24cm$ are $15cm$ and $5cm$. Find its curved surface area.

Answer 1

We have $R=15cm,r=5cm,H=24cm$

$l=\sqrt{H^2-(R-r{)}^2}$

$⟹l=\sqrt{{24}^2+{10}^2}$

$⟹l=26cm$

Curved surface area of bucket$=\pi l(R+r)=\frac{22}{7}\times 26\times 20=1634.28c{m}^2$