Question

The radii of circular ends of a bucket of height 24 cm24 cm. Find the area of its curved surface.

Answer 1

REF. Image.

Since it is a bucket. Therefore, it can act as a frustum of $h=24cm$

$r=5cm$

$R=15cm$

Slant height = $l=\sqrt{h^2+(R-r{)}^2}$

$l=\sqrt{(24{)}^2+(15-5{)}^2}=\sqrt{(24{)}^2+(10{)}^2}$

$l=\sqrt{576+100}$ $=\sqrt{676}$ $=26cm$

C.S.A$=\pi (R+r)l.$

$=\frac{22}{7}(15+5)26$

$=\frac{22}{7}\times 20\times 26$ $=\frac{11440}{7}$ $c{m}^2$

$=1634.28571c{m}^2$