The radii of maximum probability for $3 s, 3 p$ and $3 d$ electrons are in the order.

(r_{m a x})_{3 s} > (r_{m a x})_{3 p} > (r_{m a x})_{3 d}

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(r_{m a x})_{3 s} = (r_{m a x})_{3 p} = (r_{m a x})_{3 d}

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(r_{m a x})_{3 d} > (r_{m a x})_{3 p} > (r_{m a x})_{3 s}

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(r_{m a x})_{3 d} > (r_{m a x})_{3 s} > (r_{m a x})_{3 p}

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Solution

The correct option is A $(r_{m a x})_{3 s} > (r_{m a x})_{3 p} > (r_{m a x})_{3 d}$
Radius of max probability is inversely proportional to azimuthal quantum number,l.
Hence Option A is correct

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