The radii of N, $N^{3 -}$ , O and $O^{2 -}$ are in the order:

O^{2 -} > N^{3 -} > O > N

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O^{2 -} > N^{3 -} > N > O

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N^{3 -} > O^{2 -} > N > O

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O^{2 -} > N^{3 -} > N

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Solution

The correct option is A $N^{3 -} > O^{2 -} > N > O$
The radii is larger for a negative charge carrying ion than the neutral element. Also size of elements decreases towards right in a period. Thus the correct order is $N^{3 -} > O^{2 -} > N > O$

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Similar questions

o A

N^{3 -}, O^{2 -} and F^{-}

N^{3 -}, O^{2 -}

F^{-}

o A

The correct order of ionic radii of the species $N^{3 -}, O^{2 -}, N a^{+}$ and $F^{-}$ is:

A^{\circ}

N^{3 -}

O^{2 -}

F^{-}

\circ A

N^{3 -}, O^{2 -}, F^{-}

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