The radii of the circular ends of a bucket of height $40 c m$ are of lengths $35 c m$ and $14 c m$ . What is the volume of the bucket?

60060 c u b i c c m

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70040 c u b i c c m

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80080 c u b i c c m

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80160 c u b i c c m

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Solution

The correct option is D $80080 c u b i c c m$
$V = \frac{1}{3} π h (R^{2} + R r + r^{2})$
$= \frac{1}{3} \times \frac{22}{7} \times 40 (1225 + 490 + 196) c m^{3}$
$= \frac{1}{3} \times \frac{22}{7} \times 40 \times 1911 c m^{3} = 80080 c m^{3}$

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Similar questions

Q. If the radii of the circular ends of a bucket of height

40 c m

are of lengths

35 c m

and

14 c m

, then the volume of the bucket in cubic centimetres, is _________.

Q. The circular ends of a bucket are of radii 35 cm and 14 cm and the height of the bucket is 40 cm. Its volume is
(a) 60060 cm³
(b) 80080 cm³
(c) 70040 cm³
(d) 80160 cm³

Q. If the radii of the circular ends of a bucket of height 40 cm are of lengths 35 cm and 14 cm, then the volume of the bucket in cubic centimeters, is

(a) 60060

(b) 80080

(c) 70040

(d) 80160

The radii of the circular ends of a bucket of height 15 cm are 14 cm and r cm (r < 14). If the volume of bucket is 5390 $c m^{3}$ , find the value of r.

Q. The radii of the circular ends of a bucket of height 15 cm are 14 cm and r cm (r < 14). If the volume of bucket is 5390 cm³, then find the value of r. [CBSE 2011]

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The radii of the circular ends of a bucket of height 40 cm are of lengths 35 cm and 14 cm. What is the volume of the bucket?

The correct option is D 80080 cubic cmV=13πh(R2+Rr+r2)=13×227×40(1225+490+196)cm3=13×227×40×1911 cm3=80080 cm3

The radii of the circular ends of a bucket of height $40 c m$ are of lengths $35 c m$ and $14 c m$ . What is the volume of the bucket?

The correct option is D $80080 c u b i c c m$
$V = \frac{1}{3} π h (R^{2} + R r + r^{2})$
$= \frac{1}{3} \times \frac{22}{7} \times 40 (1225 + 490 + 196) c m^{3}$
$= \frac{1}{3} \times \frac{22}{7} \times 40 \times 1911 c m^{3} = 80080 c m^{3}$