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Question

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is
(a) 4900 cm2
(b) 4950 cm2
(c) 4960 cm2
(d) 4980 cm2

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Solution

(b) 4950 cm2
Let R and r be the radii of the top and base of the bucket, respectively, and let l be its slant height.
Then, curved surface area of the bucket = Curved surface area of the frustum of the cone
=πlR+r=227×45×28+7 cm2=227×45×35 cm2=4950 cm2

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