The radii of the top and bottom of a bucket of slant height $45$ cm are $28$ cm and $7$ cm respectively. The curved surface area of the bucket is

4950 {c m}^{2}

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4951 {c m}^{2}

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4952 {c m}^{2}

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4953 {c m}^{2}

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Solution

The correct option is B $4950 {c m}^{2}$
Given:
Slant Height, $l = 45$ cm
Top radius $= 28$ cm
Bottom radius $= 7$ cm
Height $= 45$ cm
Curved surface area $= π l (r_{1} + r_{2})$
$= \frac{22}{7} \times 45 (7 + 28)$
$= 4950 c m^{2}$

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The slant height of a bucket is 45 cm and the radii of its top and bottom are 28 cm and 7 cm respectively. The curved surface area of the bucket is

(a) 4953 $c m^{2}$ (b) 4952 $c m^{2}$ (c) 4951 $c m^{2}$ (d) 4950 $c m^{2}$

Q. Question 13
The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

(A)

4950 c m^{2}

(B)

4951 c m^{2}

(C)

4952 c m^{2}

(D)

4953 m^{2}

Q. The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is
(a) 4900 cm²
(b) 4950 cm²
(c) 4960 cm²
(d) 4980 cm²

Question 13
The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

(A) $4950 c m^{2}$
(B) $4951 c m^{2}$
(C) $4952 c m^{2}$
(D) $4953 m^{2}$

Q. If the radii of the ends of a bucket, 45 cm high, are 28 cm and 7 cm respectively, then the total surface area of the bucket is:

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The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm respectively. The curved surface area of the bucket is

The correct option is B 4950 cm2Given:Slant Height, l=45 cmTop radius =28 cmBottom radius =7 cmHeight =45 cmCurved surface area =πl(r1+r2)=227×45(7+28)=4950cm2

The radii of the top and bottom of a bucket of slant height $45$ cm are $28$ cm and $7$ cm respectively. The curved surface area of the bucket is

The correct option is B $4950 {c m}^{2}$
Given:
Slant Height, $l = 45$ cm
Top radius $= 28$ cm
Bottom radius $= 7$ cm
Height $= 45$ cm
Curved surface area $= π l (r_{1} + r_{2})$
$= \frac{22}{7} \times 45 (7 + 28)$
$= 4950 c m^{2}$