The radii of two circles are 8 cm and 6 cm respectively. Find the radius of the circle having its area equal to the sum of the areas of the two circles.
Let r be the radius of the circle whose area is equal to the sum of the areas of circles of radii 8 cm and 6 cm. Then,
πr2=π×82+π×62
⇒r2=100
⇒r=10 cm