The radii of two circles are 8 cm and 6 cm respectively. The diameter of the circle having area equal to the sum of the areas of the two circles (in cm) is
20
Let the radius of the required circle be r cm.
Area of required circle = area of circle of radius 8 cm + area of circle of radius 6 cm
⇒πr2=π(8 cm)2+π(6cm)2
⇒r2=64cm2+36cm2
⇒r2=100cm2
⇒r=10 cm
Thus, the diameter of the required circle is 2 × 10 cm = 20 cm.
The correct answer is C.