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Question

The radii of two circles are in the ratio 3:8. If the difference between their areas is 2695πcm2, find the area of the smaller circle.

A
441πcm2
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B
64πcm2
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C
400πcm2
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D
482πcm2
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Solution

The correct option is A 441πcm2
r1r2=38
r2=8r13
Difference between Area =2695πcm2
πr21πr22=2695π
π(r21r22)=2695π
∣ ∣π(r2164r219)∣ ∣=2695π
π(+559r21)=2695π
r21=2695π×955×π
r21=49×9
r1=7×3
=21cm
The area of the smaller circle of radius r1(21cm)
Area =πr2
=441×π
=441π

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