Question

The radioactive isotope${}_{27}^{60}\text{Co}$ which is used in the treatment of cancer can be made by $(n,p)$ reaction. For this reaction the target nucleus is:

• A. ${}_{27}^{59}\text{Co}$
• B. ${}_{28}^{60}\text{Ni}$
• C. ${}_{27}^{60}\text{Co}$
• D. ${}_{28}^{59}\text{Ni}$

Answer 1

The correct option is B ${}_{28}^{60}\text{Ni}$

${}_{28}^{60}Ni$, (n,p) means neutron attacks and proton circulates.

The reaction will be as follows:

${}_{28}^{60}Ni+C{o}^1{\to }_{27}^{60}Co+H^1$