The radioactivity of a sample is R₁ at a time T₁ and R₂ at a time T₂. If the half-life of the specimen is T, the number of atoms that have disintegrated in the time (T₂-T₁) is proportional to:

The half life of a ratio active source is T. If radio activities of the samples are $R_{1} - R_{2}$ at time

$T_{1} a n d T_{2}$ Respectively, then the number of atoms disintegrated in time $(T_{2} - T_{1})$ is proportional to

Q. The radioactivity of a sample is

R_{1}

at a time

T_{1}

and

R_{2}

at a time

T_{2}

. If the half life of the specimen is T, the number of atoms that have disintegrated in the time

(T_{2} - T_{1})

is equal to:

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The radioactivity of a sample is R1 at time T1 and R2 at time T2. If the half life of specimen is T, the number of atoms that have disintegrated in time (T2−T1) is proportional to:

The correct option is B (R2−R1)TRate =λ× Number of atoms of element yet not decayedR1=λ×N1R2=λ×N2Number of atoms decayed in time (T2−T1)=R2λ−R1λ=(R2−R1)λ=T(R2−R1)0.693∴ Number of atoms decayed in time (T2−T1)∝T(R2−R1)

The radioactivity of a sample is $R_{1}$ at time $T_{1}$ and $R_{2}$ at time $T_{2}$ . If the half life of specimen is $T$ , the number of atoms that have disintegrated in time $(T_{2} - T_{1})$ is proportional to: