The radius and height of a right circular cone are in the ratio 3:4. Then the ratio of total surface area of the cone to its curved surface area is
8:5
Let 'r' be the radius of the cone and 'h' be its height.
Given, r : h = 3 : 4.
Let r=3x and h=4x.
We know, slant height is given by,
l=√h2+r2
⟹l=√(3x)2+(4x)2
⟹l=5x
Required ratio =TSACSA=πr(r+l)πrl=(r+l)l=(3x+5x)5x=8x5x
∴Required ratio=8:5