The radius and height of an ice cream cone are in the ratio $4 : 3$ and area of its base is $154 c m^{2}$ .Find its curved surface area.

192.5 c m^{3}

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150 c m^{3}

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176.3 c m^{3}

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115.36 c m^{3}

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Solution

The correct option is A $192.5 c m^{3}$
$W e h a v e g i v e n t h e r a t i o o f r a d i u s a n d h e i g h t 3 : 4$

$S a y R a d i u s = 3 x a n d H e i g h t = 4 x$

$S l a n t H e i g h t = \sqrt{[(3 x) 2 + (4 x) 2]} a s i t g o e s t o P y t h a g o r e a n T h e o r e m$

$A r e a o f B a s e = Π x {r a d i u s}^{2}$

$154 = \frac{22}{7} * 16 x 2$

$s o s o l v i n g t h e e q w e g e t x = 1.75 c m$

$R a d i u s = 7, H e i g h t = 5.25 c m, S l a n t H e i g h t = 8.75 c m$

$C u r v e d S u r f a c e A r e a = Π x * r a d i u s x * s l a n t h e i g h t = \frac{22}{7} * 7 * 8.75 x = 192.5 c m 2$

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Similar questions

The radius and height of a cone are in the ratio 4: 3. The area of the base is 154 cm². The area of the curved surface in $c m^{2}$

The radius and height of a cone are in the ratio 4: 3. The area of the base is 154 cm². The area of the curved surface of cone is ___

4 : 3

154 c m^{2}

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