The radius and the height of a cylinder are $28$ cm and $54.5$ cm respectively. It is closed at one end by a hemisphere and at the other end by a $21$ cm high cone. Find the total surface area of the combined article.

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Solution

Surface area of cone, $π r (r + \sqrt{h^{2} + r^{2}}) = 5541.77 c m^{2}$ , where $r = 28 c m, h = 21 c m$
Surface area of hemisphere, $2 π r^{2} = 4926.015$ , where $r = 28 c m$
Curve Surface area of cylinder, $2 π r h = 9583.28 c m^{2}$
Total = $20049 c m^{2}$

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The radius and the height of a cylinder are 28cm and 54.5 cm respectively. It is closed at one end by a hemisphere and at the other end by a 21 cm high cone. Find the total surface area of the combined article.

Surface area of cone, πr(r+√h2+r2)=5541.77cm2 , where r=28cm,h=21cmSurface area of hemisphere, 2πr2=4926.015, where r=28cmCurve Surface area of cylinder, 2πrh=9583.28cm2 Total = 20049cm2

The radius and the height of a cylinder are $28$ cm and $54.5$ cm respectively. It is closed at one end by a hemisphere and at the other end by a $21$ cm high cone. Find the total surface area of the combined article.

Surface area of cone, $π r (r + \sqrt{h^{2} + r^{2}}) = 5541.77 c m^{2}$ , where $r = 28 c m, h = 21 c m$
Surface area of hemisphere, $2 π r^{2} = 4926.015$ , where $r = 28 c m$
Curve Surface area of cylinder, $2 π r h = 9583.28 c m^{2}$
Total = $20049 c m^{2}$