Question

The radius OB of a circle is perpendicular to a chord PQ of length 12 cm. If the radius meets the chord at a point A, then the length of AP =.

• A. 4 cm
• B. 5 cm
• C. 6 cm

Answer 1

The correct option is C 6 cm


From figure, it is clear that $OA\perp PQ.$
We know that the perpendicular drawn from the centre of circle to a chord bisects the chord.
$\therefore AP=AQ=\frac{PQ}{2}=\frac{12}{2}cm=6\text{cm}.$