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Nuclear Radius

The radius of...

Question

The radius of $_{13}^{27} Al$ is $3.6$ Fermi. Find the radius of $_{52}^{125} Te$

6

Fermi

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8

Fermi

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4

Fermi

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5

Fermi

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Solution

The correct option is A $6$ Fermi
$\frac{R_{1}}{R_{2}}$ = $\frac{A_{1}^{1 / 3}}{A_{2}^{1 / 3}}$
$R_{2}$ = ${(\frac{125}{27})}^{1 / 3} \times 3.6$ $= 6$ Fermi

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Similar questions

_{13}^{27} A l

3.6

_{52}^{125} T e

_{13}^{27} A l

3.6

_{52}^{125} T e

^{27} A l

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^{64} C u

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R_{0} = 1.1

Question 141

One fermi is equal to $10^{- 15}$ metre. The radius of a proton is 1.3 fermi. Write the radius of a proton (in metres) in standard form.

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