Question

The radius of ${}_{72}T{e}^{125}$ nucleus is 6 fermi. The radius of ${}_{13}A{l}^{27}$ nucleus in meters is

• A. $3.6\times {10}^{-12}m$
• B. $3.6\times {10}^{-15}m$
• C. $7.2\times {10}^{-8}m$
• D. $7.2\times {10}^{-15}m$

Answer 1

The correct option is B $3.6\times {10}^{-15}m$

$\frac{R_{Al}}{R_{Te}}={\left(\frac{A_{Al}}{A_{Te}}\right)}^{1/3}$

$R_{Al}={\left(\frac{27}{125}\right)}^{1/3}\times 6\times {10}^{-15}$

$=3.6\times {10}^{-15}m$