Question

The radius of a ball is $(5.4\pm 0.2)cm$. The percentage error in the volume of the ball is

• A. $11$%
• B. $4$%
• C. $7$%
• D. $9$%

Answer 1

The correct option is A $11$%

Volume of ball $V=\frac{4\pi }{3}{r}^3$

Percentage error in volume $\frac{\Delta V}{V}\times 100=3\times \frac{\Delta r}{r}\times 100$

So, $\frac{\Delta V}{V}\times 100=3\times \frac{0.2}{5.4}\times 100=11$ %