Question

The radius of a car tire is about 0.35 meters. If the car accelerates in a straight line from rest at 2.8 metres per second squared, what is the angular acceleration, both magnitude and direction, of the front passenger side-tire ?

• A. $8rad/s^{2}toleft$
• B. $8rad/s^{2}toright$
• C. $7rad/s^{2}toleft$
• D. $7rad/s^{2}toright$

Answer 1

The correct option is A $8rad/s^{2}toleft$

The angular acceleration is related to linear acceleration by

$\alpha =\frac{a}{r}$

Here, $a=2.8m/se{c}^2$

$r=0.35m$

Putting these values, we get,

$\alpha =8rad/s^2$

By using right hand rule, we find that the direction of the angular acceleration is to the left of the car when facing the direction in which the car moves.

Hence, option A is correct.