The radius of a circle is $2 r$ , then the volume will be

\frac{4}{3} π r^{3}

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4 π r^{3}

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\frac{8 π r^{3}}{3}

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\frac{32}{3} π r^{3}

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Solution

The correct option is D $\frac{32}{3} π r^{3}$
Volume of sphere $= \frac{4}{3} π (r a d i u s)^{3}$
$= \frac{4}{3} π (2 r)^{3} = \frac{4}{3} π \times 8 r^{3} = \frac{32}{2} π r^{3} \Rightarrow (D)$

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If the radius of a sphere is 2r, then its volume will be:

A) $\frac{4}{3} π r^{3}$
B) $4 π r^{3}$
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D) $\frac{32}{3} π r^{3}$

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The radius of a circle is 2r, then the volume will be

The correct option is D 323πr3Volume of sphere =43π(radius)3=43π(2r)3=43π×8r3=322πr3⇒(D)

The radius of a circle is $2 r$ , then the volume will be

The correct option is D $\frac{32}{3} π r^{3}$
Volume of sphere $= \frac{4}{3} π (r a d i u s)^{3}$
$= \frac{4}{3} π (2 r)^{3} = \frac{4}{3} π \times 8 r^{3} = \frac{32}{2} π r^{3} \Rightarrow (D)$