Question

The radius of a circle is $8\sqrt{2}$ cm. The length of the largest chord of that circle is

• A. $16$
• B. $32\sqrt{2}$
• C. $64\sqrt{2}$
• D. $16\sqrt{2}$

Answer 1

The correct option is D $16\sqrt{2}$

A chord intersects the circumference at two and only two points.

Now the diameter of a circle is a chord, since it intersects the circumference at two and only two points.

The lengths of all the paralles of the diameter are less than the length of the diameter.

So, diameter is the greatest chord.

Here radius $=8\sqrt{2}$ cm

$\Rightarrow$ diameter $=2\times 8\sqrt{2}$ cm $=16\sqrt{2}$ cm