wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The radius of a circle is increasing at the rate of 0.7 cm/s. What is the rate of increase of its circumference ?

A
2π cm/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.7π cm/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.4π cm/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 1.4π cm/s
Let r be the radius of circle and c be the circumference of circle.
Given that,
Radius of a circle is increasing at rate of 0.7cm/sec
i.e, drdt=0.7cm/sec(1)
we need to find rate of change of circumference of circle wrt time.
We need to calculate dcdt
we know that circumference =2πr
i.e, c=2πr
Differentiating wrt time
dcdt=d(2πr)dt
dcdt=2πdrdt
dcdt=2π×0.7
dcdt=1.4π
since, circumference is in cm 4 times is in sec
dcdt=1.4πcmsec
dcdt=1.4πcm/sec
Hence, circumference of circle is increasing at rate of 1.4πcm/sec or 1.4×3.14cm/sec=4.396cm/sec.
Hence, the answer is 1.4πcm/sec.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rate of Change
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon