The radius of a circular garden is 90 m. There is a road 9 m wide around it. Find total area of the road and the cost of levelling the road at Rs.5 per sq.m.

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Solution

Area of road i.e., area of shaded region
$= π r_{2}^{2} - π r_{1}^{2} = π (99^{2} - 90^{2}) = π (9801 - 8100)$
$= 5341.14$ sq.m
Cost of levelling
$= 5341.14 \times 5$
$= 26705.70$ Rs

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The radius of a circular garden is 90 m. There is a road 9 m wide around it. Find total area of the road and the cost of levelling the road at Rs.5 per sq.m.

Area of road i.e., area of shaded region =πr22−πr21=π(992−902)=π(9801−8100)=5341.14 sq.mCost of levelling=5341.14×5=26705.70Rs

Area of road i.e., area of shaded region
$= π r_{2}^{2} - π r_{1}^{2} = π (99^{2} - 90^{2}) = π (9801 - 8100)$
$= 5341.14$ sq.m
Cost of levelling
$= 5341.14 \times 5$
$= 26705.70$ Rs