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Standard XII

Physics

Order of Magnitude

The radius of...

Question

The radius of a hydrogen atom is $0.5 ˚ A$ . Find the order of magnitude of volume of one hydrogen atom is $10^{- 10 x}$ . The value of x is:

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Solution

Given that:
Radius is 0.5 $˚ A$ $= 0.5 \times 10^{- 10} m$ $= 5 \times 10^{- 11} m$
Volume $= \frac{4}{3} π r^{3} = \frac{4}{3} \times 3.14 \times {(5 \times 10^{- 11})}^{3}$
$= 5.23 \times 10^{- 31} m^{3}$
Hence, order of magnitude is $10^{- 31} m^{3}$ .

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The radius of a hydrogen atom is 0.5˚A. Find the order of magnitude of volume of one hydrogen atom is 10−10x. The value of x is:

Given that:Radius is 0.5˚A =0.5×10−10m =5×10−11mVolume =43πr3=43×3.14×(5×10−11)3 =5.23×10−31m3Hence, order of magnitude is 10−31m3.

The radius of a hydrogen atom is $0.5 ˚ A$ . Find the order of magnitude of volume of one hydrogen atom is $10^{- 10 x}$ . The value of x is:

Given that:
Radius is 0.5 $˚ A$ $= 0.5 \times 10^{- 10} m$ $= 5 \times 10^{- 11} m$
Volume $= \frac{4}{3} π r^{3} = \frac{4}{3} \times 3.14 \times {(5 \times 10^{- 11})}^{3}$
$= 5.23 \times 10^{- 31} m^{3}$
Hence, order of magnitude is $10^{- 31} m^{3}$ .