The radius of a semi-circular garden is $35 m$ . One has to walk ______ $m$ to make a trip along its boundary.

175

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165

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180

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110

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Solution

The correct option is C $180$
The radius of a semi-circular garden is $35 m$ .
The distance to make a trip around its boundary
$= ˆ A C B + A B$
$= π r + 2 r$
$= \frac{22}{7} (35) + 2 (35)$
$= 22 (5) + 70$
$= 110 + 70 = 180 m$
Therefore one has to walk $180 m$ to make a trip along its boundary.

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The radius of a semi-circular garden is 35 m. One has to walk ______ m to make a trip along its boundary.

The correct option is C 180The radius of a semi-circular garden is 35 m.The distance to make a trip around its boundary=ˆACB+AB=πr+2r=227(35)+2(35)=22(5)+70=110+70=180 mTherefore one has to walk 180 m to make a trip along its boundary.

The radius of a semi-circular garden is $35 m$ . One has to walk ______ $m$ to make a trip along its boundary.

The correct option is C $180$
The radius of a semi-circular garden is $35 m$ .
The distance to make a trip around its boundary
$= ˆ A C B + A B$
$= π r + 2 r$
$= \frac{22}{7} (35) + 2 (35)$
$= 22 (5) + 70$
$= 110 + 70 = 180 m$
Therefore one has to walk $180 m$ to make a trip along its boundary.