The radius of a sphere is 5 cm. Its volume will be given by (according to the theory of significant figures) :
A
523.33cm3
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B
5.23×102cm3
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C
5.0×102cm3
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D
5×102cm3
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Solution
The correct option is C5×102cm3 Volume=43πr3=43×π(5)3=523.33cm3=5.2333×102cm3 ↓ 5 significant figures Since radius has single significant figure, so, volume should also have single significant figure.
For single significant figure, we have to drop all after decimal. ⇒ Volume =5×102cm2 (if the digit to be dropped is less than 5, preceding digit is left unchanged)