Question

The radius of a sphere is measured to be 20 cm with a possible error of 0.02 of a cm. The consequent error in the surface of the sphere is

• A. 10.5 sq cm
• B. 5.025 sq cm
• C. 10.05 sq cm
• D. None of these

Answer 1

The correct option is C 10.05 sq cm

$S=4\pi r^2\therefore \delta S=8\pi r\delta x=8\pi \times 20\times .02=10.05s.cm$.