Question

The radius of a sphere shrinks from 10 cm to 9.8 cm. Find approximately the decrease in its volume.

Answer 1

Volume of sphere of radius $10cm$ $=>V_1=\frac{4}{3}\pi r^3$

$V_1=\frac{4}{3}\times 3.14\times 10\times 10\times 10$

$V_1=4186.7c{m}^3$

Now, Volume of sphere of radius $9.8cm$ $=>V_2=\frac{4}{3}\pi r^3$

$V_2=\frac{4}{3}\times 3.14\times 9.8\times 9.8\times 9.8$

$V_2=3940.45c{m}^3$

Hence, the decrease in volume will be $=4186.7-3940.45=246.24c{m}^3$