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Standard XII
Mathematics
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The radius of...
Question
The radius of a sphere shrinks from
10
to
9.8
c
m
. Find approximately the decrease in its volume.
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Solution
Let
x
be the radius and
y
be the volume. They,
y
=
4
3
π
x
3
Now,
y
=
4
3
π
x
3
⇒
d
y
d
x
=
4
π
x
2
⇒
(
d
y
d
x
)
x
=
10
=
400
π
∴
d
y
=
d
y
d
x
d
x
⇒
d
y
=
400
π
(
−
0.2
)
=
−
80
π
∴
Δ
y
=
d
y
=
−
80
π
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