The radius of a spherical nucleus as measured by electron scattering is $3.6 f m$ . What is the likely mass number of the nucleus?

27

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40

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56

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120

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Solution

The correct option is A $27$
Given,
$r = 3.6 f m$
$r_{0} = 1.2 f m$
We know that
The radius of spherical nucleus , $r = r_{0} A^{1 / 3}$
$A = (\frac{r}{r_{0}})^{3}$
$A = (\frac{3.6 f m}{1.2 f m})^{3}$
$A = 27$
The correct answer is A.

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The radius of a spherical nucleus as measured by electron scattering is 3.6 fm. What is the likely mass number of the nucleus?

The correct option is A 27Given,r=3.6fmr0=1.2fmWe know that The radius of spherical nucleus ,r=r0A1/3A=(rr0)3A=(3.6fm1.2fm)3A=27The correct answer is A.

The radius of a spherical nucleus as measured by electron scattering is $3.6 f m$ . What is the likely mass number of the nucleus?

The correct option is A $27$
Given,
$r = 3.6 f m$
$r_{0} = 1.2 f m$
We know that
The radius of spherical nucleus , $r = r_{0} A^{1 / 3}$
$A = (\frac{r}{r_{0}})^{3}$
$A = (\frac{3.6 f m}{1.2 f m})^{3}$
$A = 27$
The correct answer is A.