Question

The radius of a wheel of Shreya's cycle is 84 cm, How many revolutions will it make to go 52.5 km ?

Answer 1

Let the number of revolution be n
A/q
n× 2πr = distance
distance = 52.8×1000×100 cm
⇒n ×2π 84 = 52.8×1000×100
⇒n = ( 52.8×1000×100 )/(2π×84)
=10000
∴ number of revolution is 10000