1
Question
The radius of a wire is decreased to one third. If volume remains the same, the length will become
(a) 2 times (b) 3 times (c) 6 times (d) 9 times
The radius of a wire is decreased to one third. If volume remains the same, the length will become
(a) 2 times (b) 3 times (c) 6 times (d) 9 times
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Solution
original volume = πr²l
new radius is r/3 let new lwngth be L
new volume = π(r/3)² L
π(r/3)² L = πr²l
r²/9 L = r²l
1/9 L = l
L = 9 l
length will be 9 times the original length
new radius is r/3 let new lwngth be L
new volume = π(r/3)² L
π(r/3)² L = πr²l
r²/9 L = r²l
1/9 L = l
L = 9 l
length will be 9 times the original length
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