The radius of a wire is decreased to one-third. If volume remains the same the length will become
Wire is in the shape of a cylinder.
Let the radius of the original cylinder =r cm and height =h cm
Original volume =πr2h
New Radius after decrease =r3
Let the new height be H.
Given, πr2h=π(r3)2H
H=9h
Hence, the height becomes 9 times.