Question

The radius of base of a right circular cylinder is halved and its height is increased by 50%. The ratio of volume of the new cylinder to that of the original cylinder will be

• A. 3 : 8
• B. 2 : 1
• C. 3 : 1
• D. 4 : 1

Answer 1

The correct option is A 3 : 8

$\frac{V_2}{V_1}=\frac{\pi {\left(\frac{r}{2}\right)}^2\left(\frac{3h}{2}\right)}{\pi r^{2}h}=\frac{3}{8}\Rightarrow V_2:V_1=3:8.$