The radius of curvature of $9 x^{2} + 4 y^{2} = 36$ is greatest at the point:

(0, 2)

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(2, 0)

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(0, 3)

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(\sqrt{3}, \frac{3}{2})

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Solution

The correct option is B $(2, 0)$

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Similar questions

e_{1}, e_{2}

9 x^{2} + 4 y^{2} = 36

9 x^{2} - 4 y^{2} = 36,

e_{1}

e_{2}

9 x^{2} + 4 y^{2} = 36

9 x^{2} - 4 y^{2} = 36

4 y^{2} - 9 x^{2} = 36

The graph of the linear equation 2x + 3y = 6 meets the y - axis at the point

(a) (2, 0)

(b) (3, 0)

(d) (0, 3)

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