Object distance, u = -3.5 m
Radius of curvature, R = 2 m
Using,
f=R/2
f=1m
1/f = 1/v + 1/u
1 = 1/v – 1/3.5
=> 1/v = 1 + 1/3.5
=> v = 0.77 m
The image is at a distance 0.77 m from the mirror on the side opposite to the object.
Size of the image is = -v/u = -0.77/(-3.5) = 0.22
The size of the image is 0.22 times the object. The image is virtual, diminished and erect.