The radius of curvature of a convex mirror used on a moving atomic is 2.0 m. A truck is coming behind it at a constant distance of 3.5 m. calculate
(a) The position, and the size of image relative to the size of the truck.
(b) What will be the nature of the image?

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Solution

now $m$ = $- \frac{v}{u}$
= $- \frac{0.77}{- 3.5}$
= $\frac{1}{4.5}$

As m is positive so image form will be virtual and erect

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The radius of curvature of a convex mirror used on a moving atomic is 2.0 m. A truck is coming behind it at a constant distance of 3.5 m. calculate(a) The position, and the size of image relative to the size of the truck.(b) What will be the nature of the image?

now m = −vu =−0.77−3.5 =14.5As m is positive so image form will be virtual and erect

The radius of curvature of a convex mirror used on a moving atomic is 2.0 m. A truck is coming behind it at a constant distance of 3.5 m. calculate
(a) The position, and the size of image relative to the size of the truck.
(b) What will be the nature of the image?

now $m$ = $- \frac{v}{u}$
= $- \frac{0.77}{- 3.5}$
= $\frac{1}{4.5}$

As m is positive so image form will be virtual and erect