The radius of electron's second stationary orbit in Bohr's atom is R. The radius of the third orbit will be

3 R

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2.25 R

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9 R

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\frac{R}{3}

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Solution

The correct option is B $2.25 R$
$r α n^{2} \Rightarrow \frac{r_{(2)}}{r_{(3)}} = \frac{4}{9} \Rightarrow r_{(3)} = \frac{9}{4} R = 2.25 R$

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