The radius of first Bohr orbit in hydrogen atom is $r_{0}$ then the radius of first orbit in helium atom will be

2 r_{0}

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4 r_{0}

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\frac{r_{0}}{2}

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r_{0}

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Solution

The correct option is C $\frac{r_{0}}{2}$
Radius of nth orbit in any atom $r_{n} = \frac{0.529 n^{2}}{Z}$
For Hydrogen atom, $Z = 1$ and $r_{1} = r_{o}$
$∴$ $r_{o} = 0.529$
For Helium, $Z = 2$
Radius of first orbit in helium $r_{1}^{'} = \frac{0.529}{2} = \frac{r_{o}}{2}$

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