The radius of gyration of a solid sphere of radius R about a certain axis is R. The distance of this axis from the centre of the sphere is
A
R
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B
√0.5R
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C
√0.6R
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D
√0.4R
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Solution
The correct option is B√0.6R I=mk2 (where k is the radius of gyration.) I=mr2....(i) Also I=ICM+mh2 =25mr2+mh2.....(ii) From (i) and (ii) mr2=25mr2+mh2 35mr2=mh2⇒h2=35r2 ∴h=√0.6r.