The radius of gyration of a uniform rod of length L, about an axis passing through its centre of mass and perpendicular to it's length is:
A
L2√3
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B
L212
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C
L√3
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D
L√2
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Solution
The correct option is AL2√3 For a rod the MOI about an axis passing through its centre of mass and ⊥ to its plane is; I=mL212....(i)
Let the radius of gyration about the same axis is k, I=mk2...(ii)
From both equations: mL212=mk2 ⇒k=√L212 ∴k=L2√3