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Question

The radius of gyration of a uniform rod of length l, about an axis passing through a point 14 away from the centre of the rod, and perpendicular to it, is

A
18l
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B
38l
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C
748l
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D
14l
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Solution

The correct option is C 748l
As we know that moment of inertia of the rod about its centre of mas,

Icm=Ml212

Using parallel axis theorem, Moment of inertia of the rod about an axis passing through a point 14 away from centre of the rod,

I=Ml212+M×(14)2

I=7Ml248

If K is radius of gyration, then

MK2=7Ml248

K=748l
Final answer is (b)

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