Question

The radius of $H-$ atom in its ground state is $0.53A^{\circ }$. The radius of $L{i}^{2+}$ in the similar is:

• A. $0.058A^{\circ }$
• B. $0.171A^{\circ }$
• C. $0.706A^{\circ }$
• D. $1.06A^{\circ }$

Answer 1

Answer: (B)

$0.171A^{\circ }$

$r_{L{i}^{2+}}=\frac{r_H\times n^2}{Z}$
Here, $n=1$, (due to similar state)
$Z=3$
$r_{L{i}^{2+}}=\frac{0.53\times (1{)}^2}{3}$
$=0.171A^{\circ }$