The radius of $L a^{3 +}$ (atomic number = 57) is 1.06 A.Which one of the following given values will be closest to the radius of $L u^{3 +}$ (atomic number = 71)?

0.85 A

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1.06 A

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1.40 A

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1.60 A

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Solution

The correct option is A 0.85 A
Due to Lauthanoid contraction radii of $L u^{+ 3} < r a d i i o f L a^{+ 3}$
So it will $0 \cdot 85 A^{0} < 1 \cdot 06 A^{0}$

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Similar questions

The radius of $L a^{3 +}$ (At. No. of La = 57) is 1.06 A $^{0}$ . Which one of the following given values will be closest to the radius of $L u^{3 +}$ ?( Atomic number of Lu=71)

Q. The radius of

{L a}^{3 +}

(Atomic number of

L a = 57

) is

1.06 A

Which one of the following given values will be closest to the radius of

{L u}^{3 +}

(Atomic number of

L u = 71

Q. The radius of

L a^{3 +}

(At.No. of La = 57) is 1.06A. Which one of the following given values will be closest to the radius of

L u^{3 +}

(At.No. of Lu = 71)

Q. The ionic radius of

_{57} L a^{3 +}

is 1.06 A. Which one of the following given values will be closest to the ionic radius of

_{71} L u^{3 +} ?

The correct order of ionic radius for $Y^{3 +}, L a^{3 +}, E u^{3 +}$ and $L u^{3 +}$ is:

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The radius of La3+ (atomic number = 57) is 1.06 A.Which one of the following given values will be closest to the radius of Lu3+ (atomic number = 71)?

The correct option is A 0.85 ADue to Lauthanoid contraction radii of Lu+3<radiiofLa+3So it will 0⋅85A0<1⋅06A0

The radius of $L a^{3 +}$ (atomic number = 57) is 1.06 A.Which one of the following given values will be closest to the radius of $L u^{3 +}$ (atomic number = 71)?

The correct option is A 0.85 A
Due to Lauthanoid contraction radii of $L u^{+ 3} < r a d i i o f L a^{+ 3}$
So it will $0 \cdot 85 A^{0} < 1 \cdot 06 A^{0}$