The radius of $L a^{3 +}$ (Atomic number of $L a = 57$ ) is $1.06 ˚ A$ . Which one of the following given values will be closest to the radius of $L u^{3 +}$ (Atomic number of $L u = 71$ )?

1.40 ˚ A

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1.06 ˚ A

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0.85 ˚ A

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1.60 ˚ A

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Solution

The correct option is C $0.85 ˚ A$
The ionic radii of $L n^{3 +}$ reduces from $L a^{3 +}$ to $L u^{3 +}$ due to Lanthanide Contraction. Therefore the lowest value here must be the one closest ionic radii of $L u^{3 +} ⟹ 0.85 A .$

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Similar questions

Q. The radius of

{L a}^{3 +}

(Atomic number of

L a = 57

) is

1.06 A

Which one of the following given values will be closest to the radius of

{L u}^{3 +}

(Atomic number of

L u = 71

Q. The radius of

L a^{3 +}

(At.No. of La = 57) is 1.06A. Which one of the following given values will be closest to the radius of

L u^{3 +}

(At.No. of Lu = 71)

The radius of $L a^{3 +}$ (At. No. of La = 57) is 1.06 A $^{0}$ . Which one of the following given values will be closest to the radius of $L u^{3 +}$ ?( Atomic number of Lu=71)

Q. The radius of

L a^{3 +}

(atomic number = 57) is 1.06 A.Which one of the following given values will be closest to the radius of

L u^{3 +}

(atomic number = 71)?

Q. The radius of

L a^{+ 3} (Z = 57)

1.06 A^{\circ}

. Which of the following given values is closest to the radius of

L u^{2 +} (Z = 71)

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The radius of La3+(Atomic number of La=57) is 1.06˚A. Which one of the following given values will be closest to the radius of Lu3+ (Atomic number of Lu=71)?

The correct option is C 0.85˚AThe ionic radii of Ln3+ reduces from La3+ to Lu3+ due to Lanthanide Contraction. Therefore the lowest value here must be the one closest ionic radii of Lu3+⟹0.85A.

The radius of $L a^{3 +}$ (Atomic number of $L a = 57$ ) is $1.06 ˚ A$ . Which one of the following given values will be closest to the radius of $L u^{3 +}$ (Atomic number of $L u = 71$ )?

The correct option is C $0.85 ˚ A$
The ionic radii of $L n^{3 +}$ reduces from $L a^{3 +}$ to $L u^{3 +}$ due to Lanthanide Contraction. Therefore the lowest value here must be the one closest ionic radii of $L u^{3 +} ⟹ 0.85 A .$