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Bohrs Derivations

The radius of...

Question

The radius of $N a^{+}$ is 95 pm and that of $C l^{-}$ ion is 181 pm. Hence, the coordination number of $N a^{+}$ will be:

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Solution

The correct option is B 6
$\frac{r^{+}}{r^{-}} = \frac{95}{181} = 0.524$
Limiting radius ratio is $0.524$ . Therefore, the coordination number is $6$ .

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Similar questions

The radius of Na⁺ ion is 95pm and that of Cl^- ion is 181pm. Predict whether the coordination number of Na⁺ ion is 6 or 4 ?

N a^{+}

95

C l^{-}

181

N a^{+}

95

C l^{-}

181

N a^{+}

6

4

N a^{6}

N a^{4}

N a^{+}

C l^{-}

95 p m

181 p m

N a C l

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