The radius of proton is 0-6- 10-15 m- What is the order of magnitude of it volume-

The correct option is B 10^ 45 m^3 The volume of the proton is V=43π r^3=43× 3.14× (0.6× 10^ 15)^3=9.04× 10^ 46 m^3 According to rule of order of mag ...

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Standard XII

Chemistry

Thomson's Discovery of Electrons

The radius of...

Question

The radius of proton is $0.6 \times 10^{- 15} m$ . What is the order of magnitude of it volume?

10^{- 47} m^{3}

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10^{- 44} m^{3}

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10^{- 45} m^{3}

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10^{- 46} m^{3}

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Solution

The correct option is B $10^{- 45} m^{3}$
The volume of the proton is $V = \frac{4}{3} π r^{3} = \frac{4}{3} \times 3.14 \times (0.6 \times 10^{- 15})^{3} = 9.04 \times 10^{- 46} m^{3}$
According to rule of order of magnitude , as $9.04 > 5$ so it will be taken 10.
Thus, order of magnitude of volume $= 10 \times 10^{- 46} = 10^{- 45} m^{3}$

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The radius of proton is 0.6×10−15m. What is the order of magnitude of it volume?

The correct option is B 10−45m3The volume of the proton is V=43πr3=43×3.14×(0.6×10−15)3=9.04×10−46m3According to rule of order of magnitude , as 9.04>5 so it will be taken 10.Thus, order of magnitude of volume =10×10−46=10−45m3

The radius of proton is $0.6 \times 10^{- 15} m$ . What is the order of magnitude of it volume?